A randomized block design has three levels of factor A and five levels of factor
ID: 3202638 • Letter: A
Question
A randomized block design has three levels of factor A and five levels of factor B where six replicates for each combination are examined. The results include the following sum of square terms:
SST = 1,572 SSA = 1,038 SSB = 346 SSAB = 33 Use Table 4
Construct an ANOVA table.
A randomized block design has three levels of factor A and five levels of factor B where six replicates for each combination are examined. The results include the following sum of square terms:
SST = 1,572 SSA = 1,038 SSB = 346 SSAB = 33 Use Table 4
a.Construct an ANOVA table.
Explanation / Answer
here level of A =a =3
level of B=b=5
and replicates =c=6
variation sum of square(SS) degree of freedom(df) mean sum of square=SS/df F value A 1038 a-1 =2 519.000 MSA/MSE=251.088 B 346 b-1 =4 86.500 MSB/MSE=41.855 AB 33 (a-1)(b-1)=8 4.125 MSAB/MSE=1.996 Error 155 ab(c-1) =75 2.067 total 1572 abc-1=89Related Questions
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