Janine is an ambidextrous volleyball player. She is practice \"short serves\" in
ID: 3203262 • Letter: J
Question
Janine is an ambidextrous volleyball player. She is practice "short serves" in volleyball because her team has an upcoming match against an opponent who does not pass short serves very well. Janine must land a majority of her "short serves" in bounds or her coach will not let her use her short serve i an upcoming match. When serving left-handed Janine makes 23 out of 30 serves. What is the parameter in this scenario? What are two possible explanations for Janine getting 23 out of 30 left-handed short serves bounds? Using an applet, simulate 1000 repetitions of having Janine serve 30 right-handed short serve she is just as likely to serve in as she is to not serve in. Where is the distribution centered? Based on the value of the statistic, do you think the chance model is wrong? Why or why not Are the results of this study statistically significant or is the chance model plausible? How are you deciding?Explanation / Answer
1) The paramter in this situation is the proportion of short serves that Janine would do in the 30 serves played
2) The 2 possible explanations can be the effect of
the fear of not being selected in the game , so she brings her "A" game
The other explanation can be that it is just due to chance
3)
We shall simulate this using the open sourc epackage R . The complete R snippet is as follows
# we shall assume that majority is above 15 , size is 30 , as 30 serves
dbinom(16, size=30, prob=0.5)
#now we need to replicate this 1000 times
reps<- 1000
# replciate this 1000 times
x1 <- replicate(reps, dbinom(round(runif(1,min=15,max=30)), size=30, prob=0.5))
# calculate mean
mean(x1)
The result is mean(x1)
[1] 0.03226073
Based on this the average chance that she will serve more than 15 in serves is just 3% , hence the fact that she was able to serve 23 in out of 30 is purely due to chance
Kindly note that we can answer only 4 subparts of a question , at a time
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