Explain the difference between the answer to (d) and (e). Suppose that two cards

Question

Explain the difference between the answer to (d) and (e). Suppose that two cards are to be randomly selected from a standard deck of 52 playing cards, without replacement. What is the probability that both cards are red? What is the probability that the first card is an ace and the second card is either a ten, jack, queen, or king? If you were returning the card to the deck before selecting the second card, what would be your answers in (a) and in (b)? Suppose that you believe that the probability that you will get a grade of B or above in Statistics is 0.6

Explanation / Answer

a) as there are 26 red cards out of 52

hence probabilty that 1st card is red =26/52

after first card is drawn and if it is red, 25 red cards left out of 52,

hence probabilty of first and second card to be red =(26/52)*(25/51) =25/102

b)as there are 4 aces in 53 cards

hence probabilty of ace in first draw =4/52

after drawing an ace 51 cards left out of them either ten,jack, king or queen are 16 cards

hence requierd probability =(4/52)*(16/51) =16/663

c) first case a)

as after drawing first card again 26 red are there out of 52

hence probabilty =(26/52)*(26/52) =1/4

case b) on similar line probabilty =(4/52)*(16/52) =4/169

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