The label on boxes of laundry detergent claims the boxes contain 39 ounces of de
ID: 3204055 • Letter: T
Question
The label on boxes of laundry detergent claims the boxes contain 39 ounces of detergent. There is, however, some variability in the filling process. The amount of laundry detergent per box is known to follow a normal distribution. We take a random sample of 10 boxes and measure the contents. The data are as follows:
39.8 38.6 38.3 39 38 39.6 38.6 38.2 39 37.8
The sample mean and sample standard deviation are calculated to be 38.69 and 0.66, respectively.
We would like to conduct a hypothesis test to determine if there is sufficient evidence that the mean amount of detergent per box is less than 39.
Suppose we had instead used the critical value method to conduct the test. We would reject Ho if: A) t 1.372 B) It 1.383 C) t 1.833 D) t s -1.812 O E) It 1.812 F) ts -1.383 G) ts -1.833 H) t 1.812 O I) It 2 1.372 O J) t -1.372 K) t 21.383 O L) It 2 1.833Explanation / Answer
here std errror =std deviation/(n)1/2 =0.66/(10)1/2=0.2087
value of test stat =(Xbar-mean)/std error =(38.69-39)/0.2087= -1.4854
p vlaue for above tstat at (n-1=9) degree of freedom =0.0858
as p value is less then 0.1 level of significance we reject null hypothesis that mean is equal to 39.
for 10% level of significance at 9 degree of freedom , tcritical; for Ho to be rejected t<=-1.3830
option F
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