The enrollments at random selection of independent religiously controlled underg

Question

The enrollments at random selection of independent religiously controlled undergraduate school are indicated below. Find the mean, median, mode, and midrange. Compare the mean and median and what that says about the data. (1494 .6 141b.5; none; 1777.5) 1023 1080 1106 1197 1241 1371 1409 1422 1469 1484 1648 1860 2082 2532 An instructor grades exams, 20%; Term paper 30%; Final exam 50%. A student had grades of 83, 72, & 90, respectively, for exams, term paper & final exam. Find the student's final average. Use weighted mean. Another Instructor gives four 1-hour exams and one final exam, which counts as two 1-hour exams. Find a student's grade if she received 62, 83, 97, and 90 on the 1-hour exams and 82 on the final exam.

Explanation / Answer

9) putting data into acending order

here mean =total/n =20924/14=1494.57

median =(n+1)/2 th value =(14+1)/2 th value =7.5 th value =(7+8)th value/2 =(1409+1422)/2 =1415.5

mode=this has none each data represent itself only once.

mid range =(maximum+minimum)/2 =(1023+2532)/2 =1777.5.

as mid range is far away from median, and mean is greater then median, this data is right skewed with more values on the right tail,

27) as weighted average=(w1x1+w2x2+w3x3+...)/(w1+w2+w3+..)

hence weighted average mean =(0.2*83+0.3*72+0.5*90)/(0.2+0.3+0.5) =83.2

28) weighted average grade =(62*1+83*1+97*1+90*1+82*2)/(1+1+1+1+2) =82.67

X 1023 1080 1106 1197 1241 1371 1409 1422 1469 1484 1648 1860 2082 2532

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