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There are 5 dice in a bag: two tetrahedrons (4-sided), one cube (6-sided), and t

ID: 3206601 • Letter: T

Question

There are 5 dice in a bag: two tetrahedrons (4-sided), one cube (6-sided), and two octahedrons (8-sided). I grab a dice at random (i.e., the probability of picking any dice is 1/5) and roll it. What is the probability of picking an octahedron? Suppose I tell you that the result of the roll is a 3, what is the probability that the dice I picked is a tetrahedron? Which dice is most likely if I tell you that the result of the dice is a 6? A tetrahedron, a cube, or an octahedron? Which dice is most likely if I tell you that the result of the dice is a 7?

Explanation / Answer

a) there are two octahedron , since all are equal probable = and there are two octahedrons = We can say that picking an octahedron probability = 2C1 /5C1 = 0.4

b) 3 is present on all the dice , so picking a tetrahedron is same as in question(a) = 2C1/5C1 = 0.4

c) If result is 6 , we know for sure it cant be a tetrahedron , so remaining left 1 cube , 2 octahedron

Picking an octahedron is most probable sinc they are large in number

d) If result is 7 , we know for sure it can only be octahedron