A starting lineup in basketball consists of two guards, two forwards, and a cent

Question

A starting lineup in basketball consists of two guards, two forwards, and a center. (a) A certain college team has on its roster three centers four guards, five forwards, and one individual (X) who can play either guard or forward. How many different starting lineups can be created? [Hint: Consider lineups without X, then lineups with X as guard, then lineups with X as forward.] 390 lineups (b) Now suppose the roster has 3 guards, 4 forwards 3 centers, and 2 "swing players" (X and Y) who can play either guard or forward. If 5 of the 12 players are randomly selected, what is the probability that they constitute a legitimate starting lineup? (Round your answer to three decimal places.)

Explanation / Answer

Solution:-

5/12 x 100% Divided by 5 by 12 and multiply it by 100% = 0.4166 x 100% = 41.66%
The probability that they constitute a legitimate starting up line is 41.66%
But the probability can't always be statistically significant because they were randomly selected. The average probability would be 41.66% though.

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