9 of 19 (0 complete) v in a survey of a group of men, the heights in the 20-29 a

Question

9 of 19 (0 complete) v in a survey of a group of men, the heights in the 20-29 age group were normally distributed wth a mean 6T1 inches and a standard deviation of30 inches A study participant is tandomly selected Compiete pats (a) through Find the probabilitythat a study pancipant has a height that is less than 6Tinches The probabley that the stady participant selected at random is less than 67 inches tallis Round to bur decimal places as needed) (bl Find he probablity that a study panopant has a height that is between 67 and inches The probabley that ene study participat selected sandams beweener and roheswis Roundtotour decima places as needed le Find the probability that a study paticipant has a height that is more than 72 inches probabiny that the study participarn selected atrandomis thanr2nchestal Rundt lourd oma place as need dentify any unusual events Explan your reasoning Choosethe conect answer below There are no unusual ets because all the pobabilies are greae than 0s oB. The events in pans and to) ae unusual because pobabilti s has O c. The events in puns lal, (b), and lo) ae unusuaal because al their prabatiiies are lossthan005 O D. The event in pat unusual because Rs pr baliity is less than 6 ciekto select your answeris O

Explanation / Answer

= 67.1, = 3

(a) x = 67

z = (x - )/ = (67 - 67.1)/3 = -0.0333

P(x < 67) = P(z < -0.0333) = 0.4867

(b) z = (x - )/ = (72 - 67.1)/3 = 1.6333

P(67 < x < 72) = -0.0333 < z < 1.6333) = 0.4621

(c) P(x > 72) = P(z > 1.6333) = 0.0512

(d) Option (A).

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