I am at a casino playing blackjack. To win the most money I need to get a \"natu

Question

I am at a casino playing blackjack. To win the most money I need to get a "natural" blackjack with the first 2 cards I am dealt. A natural blackjack occurs when you are dealt a card with a value of 10 (a jack, queen, king, or 10 any suit) and an ace (any suit). If I am dealt the first 2 cards from the deck, what is the probability I will get a natural blackjack? If you need to know, there are 4 kings, 4 queens, 4 jacks, 4 tens, and 4 aces in a deck of cards. A deck of cards contains a total of 52 cards

Explanation / Answer

For a card to be a ten, jack, queen or king, as there are 4 suits, number of such cards = 4*4 = 16

For a card to be ace, number of such cards = 4

P(natural blackjack) = 16C1*4C1 / 52C2 = 0.0483

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