Find the equation of the tangent line to the curve when x has the given value. f

Question

Find the equation of the tangent line to the curve when x has the given value. f(x) = 8 / x + 1; x = 2 y = 8 / 9x + 8 / 9 y = -8 / 9x + 40 / 9 y = -16 / 9x + 40 / 9 y = -8 / 9x + 8 / 9 5x2 + 7x - 9 / -6x2 + 2 0 infinity -2 / 9 -5 / 6 Find all points where the function is discontinuous None x = 1 x = -2 x = - 2, x = 1 Given an appropriate answer Find the instantaneous rate of change for the function f(x) = 5x2 + x at x = -4 -39 6 -41 -14 solve the problem. Suppose that the total profit in hundreds of dollars from selling x items is given by p(x) = -x2 + 12x - 33.Find the marginal profit at

Explanation / Answer

f(x)=8/(x+1) f'(x)=-8/(x+1)2 at x=2 f'(2)=-8/9 f(2)=8/3

equation of tangent at x1,y1 to f(x) is

y-f(x1)=f'(x1)[x-x1]

hence equation will be y-f(2)=f'(2)(x-2) i.e. y-(8/3)=(-8/9)(x-2) i.e 9y+8x-40=0 is the equation of tangent.

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