A Survey reveals that the waiting time for the bus service 179 during off-peak h
ID: 3216830 • Letter: A
Question
A Survey reveals that the waiting time for the bus service 179 during off-peak hours is approximated by a normal distribution, whose mean and standard deviation are respectively 7 and 2 minutes. Find the probability of waiting for less than 6 minutes before boarding (4 decimals). Tries remaining: 2 Marked out of 2.00 Y Flag Question Tries remaining: 2 Marked out of 2.00 Y Flag Question Answer: Check Find the probability of waiting for more than 8 minutes before boarding (4 decimals). Answer: Check Assume that you have waited 5 minutes at the bus stop. What is the probability that you wait for a total of more than 8 minutes before boarding (4 decimals)? Tries remaining: 2 Marked out of 2.00 Y Flag question I = i Answer: CheckExplanation / Answer
mean = 7 ,std.deviation = 2
a)
By normal distribution formula,
z = ( x - mean) / s
= (6 - 7) / 2
= -0.5
Now,we need to find p( z < -0.5)
p(x < 6) = p( z < -0.5) = 0.3085
b)
By normal distribution formula,
z = ( x - mean) / s
= (8 - 7) / 2
= 0.5
Now,we need to find p( z > 0.5)
p(x >8 ) = p( z >0.5) = 0.3085
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