s^2 is a point estimator of a. mu b. p C. sigma^2 What is the value for x_.025^2

Question

s^2 is a point estimator of a. mu b. p C. sigma^2 What is the value for x_.025^2 with 29 degrees of freedom? a. 42.557 b. 17.708 c. 45.722 d. 16.047 What is the probability that a x^2 value is less than 16.047 with 29 degrees of freedom? a. .975 b. .025 c. .95 d. .05 What is the value for F_.05 with df_n = 10 and df_d = 20? a. 2.35 b. 2.77 c. 3.37 d. 3.42 Suppose that we would like to make inferences about two population variances. What is the F stat if we have 15 and 30 as our sample variances? a. .5 b. 1 c. 1.5 d. 2

Explanation / Answer

1) 2

2) 45.722(using chi square table right tailed)

3) 16.047with 29 drees of freedom is with p = 0.975, Therefore, the area to the left is 1 - 0.975 = 0.025

4) 2.35 (from f table, df numerator is 10 and df denominator is 20)

5) s12/s22 is the test statistic with s12 being the bigger variance of the two. 30/15 = 2(answer)

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.