A salesman normally makes a sale (closes) on 80% of his presentations. Assuming

Question

A salesman normally makes a sale (closes) on 80% of his presentations. Assuming the presentations are independent, find the probability of each of the following. He fails to close for the first time on his fifth attempt He closes his first presentation on his fourth attempt. The first presentation he closes will be on his second attempt. The first presentation he closes will be on one of his first three attempts. The probability he fails to close for the first time on his fifth attempt is .0819 (Round to four decimal places as needed. The probability he closes his first presentation on his fourth attempt is (Round to four decimal places as needed.)

Explanation / Answer

Probability that a salesman succeed is p=0.8

(a)
Here he succeed in 4 consecutive attempts and fails the fifth one
Hence probability is (0.8)^4*(0.2) = 0.0819

(b)
Here he fails the first 3 attempts and succeed in the fouth.
Hence probability is (0.2)^3*(0.8) = 0.0064

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.