Ronin is a Human Resources Manager at Burgerville. He wants to add a personality

Question

Ronin is a Human Resources Manager at Burgerville. He wants to add a personality test to the selection tools for cashiers under the assumption that more agreeable employees will have significantly (alpha = .05) more satisfied customers. Before adding an agreeableness survey to the selection tools, he administers the following agreeableness survey to current employees. I see myself as someone who. is considerate and kind to almost anyone. 0 (completely disagree), 1 (strongly disagree), 2 (disagree), 3 (neither agree nor disagree), 4 (agree), 5 (strongly agree). 6 (completely agree) is sometimes rude to others. 0 (completely disagree), 1 (strongly agree), 2 (agree), 3 (neither agree nor disagree), 4 (disagree), 5 (strongly disagree), 6 (completely agree) can be cold and aloof. 0 (completely disagree), 1 (strongly agree), 2 (agree), 3 (neither agree nor disagree), 4 (disagree), 5 (strongly disagree), 6 (completely agree) He also administer the following customer satisfaction survey to customers for 2 weeks. My cashier was friendly today 0 (completely disagree). 1 (strongly disagree), 2 (disagree), 3 (neither agree nor disagree), 4 (agree), 5 (strongly agree), 6 (completely agree) My cashier helped me have a pleasant dining experience today, 0 (completely disagree), 1 (strongly disagree), 2 (disagree) 3 (neither agree nor disagree), 4 (agree), 5 (strongly agree), 6 (completely agree) My cashier's name was: ___ What is the critical value for the data below (X = mean agreeableness and Y = mean customer satisfaction)? r crit = .805 r crit = .878 r crit = .669 r crit = .754

Explanation / Answer

ANSWER: r crit = 0.878 (two-tailed test)

EXPLANATION:

Given that n = 5 ALPHA = 0.05

AT alpha = 0.05 level of significance with (5-2) = 3 degrees of freedom, the critical value of 'r' is given by

r crit = 0.878 (two-tailed test)

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