Ronin is a Human Resources Manager at Burgerville. He wants to add a personality

Question

Ronin is a Human Resources Manager at Burgerville. He wants to add a personality test to the selection tools for cashiers under the assumption that agreeableness will be a significant (alpha = .05) predictor or more satisfied customers. Before adding an agreeableness survey to the selection tools, he administers the following agreeableness survey to current employees. I see myself as someone who. is considerate and kind to almost anyone. 0 (completely disagree), 1 (strongly disagree), 2 (disagree), 3 (neither agree nor disagree), 4 (agree), 5 (strongly agree), 6 (completely agree) is sometimes rude to others. 0 (completely disagree), 1 (strongly agree), 2 (agree), 3 (neither agree nor disagree), 4 (disagree), 5 (strongly disagree), 6 (completely agree) can be cold and aloof. 0 (completely disagree), 1 (strongly agree), 2 (agree), 3 (neither agree nor disagree), 4 (disagree), 5 (strongly disagree), 6 (completely agree) He also administer the following customer satisfaction survey to customers for 2 weeks. My cashier was friendly today 0 (completely disagree). 1 (strongly disagree), 2 (disagree), 3 (neither agree nor disagree), 4 (agree), 5 (strongly agree), 6 (completely agree) My cashier helped me have a pleasant dining experience today, 0 (completely disagree), 1 (strongly disagree), 2 (disagree) 3 (neither agree nor disagree), 4 (agree), 5 (strongly agree), 6 (completely agree) My cashier's name was: ___ What is the regression equation for the data below (X = mean agreeableness and Y = mean customer satisfaction)? predicted Y = 1.786(X)+ 2.715 predicted Y = 1.786(X) + 2.715 predicted Y = .938(X) - .002 predicted Y = .926 (X) + .037

Explanation / Answer

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Here the regression equation is predicted Y = 1.786 X - 2.715

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