Hi Please , l want to you to answer the All questions (a , b , c , d ) in the Qu

Question

Hi

Please , l want to you to answer the All questions (a , b , c , d ) in the Quiz page.

Thank you so much

Quiz Each respondent in the CurrentPopulationSurvey ofMarch 1993 was classified as employed, unemployed, or outside the labor force. Ther for men inCaliforniaage35-44 can be cross-tabulated by marital status, as follows: Widowed divorced Never Married or separated married Employed 679 103 114 Unemployed 69 11 13 Not in labor force 60 16 Men of different marital status seem to havedifferentdistributions oflabor force status. Or is this just chancevariation? Use the chi-square test to see if laborstatus and marital status are dependent. Make sure you setup the null and alternate hypothesis, report the chi-square statistic and p-value and draw conclusions. For the men who were Employed test the following hypothesis: Ho: Married Ha: Atleast one of the cell probabilities is different. Make sure you report the chi-square statistic and p-value and draw conclusions. This is like the problems in 10.4) For the men who were "Unemployed" testthe following hypothesis Ho: TTMarried Ha: Atleast one of the cell probabilities is different. Make sure you report the chi-square statistic and p-value and drawconclusions. This is like the problems in 10.4) For the men who were Not in the labor force 'test the following hypothesis: Ho: TT Married Ha: Atleast one of the cell probabilities is different. Make sure you report the chi-square statistic and p-value and draw conclusions. This i like the problems in 10.4)

Explanation / Answer

a)

for above chi stat X2 =4.162

and p value=0.3845

as p value is higher then 0.05 level we can not reject that martial status and employment status are independent.

b)

here chi stat X2 =0.586

and p value =0.7460

as p value is higher then 0.05 level we can not reject that proportion distribution are as per null hypothesis

c)

chi stat =0.346 ; p value=0.8413

as p value is higher then 0.05 level we can not reject that proportion distribution are as per null hypothesis

d)

chi stat x2 =3.767

and p value=0.1521

as p value is higher then 0.05 level we can not reject that proportion distribution are as per null hypothesis

Observed O married Widowed Never married Total Employed 679 103 114 896 Unemployed 69 11 13 93 Not in labor force 60 16 9 85 Total 808 130 136 1074 Expected E=rowtotal*column total/grand total married Widowed Never married Total Employed 674.086 108.454 113.460 896 Unemployed 69.966 11.257 11.777 93 Not in labor force 63.948 10.289 10.764 85 Total 808 130 136 1074 chi square =(O-E)^2/E married Widowed Never married Total Employed 0.036 0.274 0.003 0.313 Unemployed 0.013 0.006 0.127 0.146 Not in labor force 0.244 3.170 0.289 3.703 Total 0.293 3.451 0.419 4.162

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