A histogram of time spent eating and drinking each day is skewed right. Use this

Question

A histogram of time spent eating and drinking each day is skewed right. Use this result to explain why a large sample size is needed to construct a confidence interval for the mean time spent eating and dirking each day. Since the distribution of time spent eating and drinking each day is not normally distributed (skewed right), the sample must be large so that the distribution of the sample mean will be approximately normal. The distribution of the sample mean will always be approximately normal. The distribution of the sample mean will never be approximately normal. Since the distribution of time spent eating and drinking each day is normally distributed, the sample must be large so that the distribution of the sample mean will be approximately normal. In 2010, there were over 200 million people nationally age 15 or older. Explain why this, along with the fact that the data were obtained using a random sample, satisfies requirements for constructing a confidence interval. The sample size is greater than 5% of the population. The sample size is greater than 10% of the population. The sample size is less than 5% of the population. The sample size is less than 10% of the population. Determine and interpret a 99% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day.

Explanation / Answer

a) option A is correct; as according to central limit theorum for population which are not normally distributed we would need larger sample size

b)option c is correct

c)sample mean =1.72 Hours

for std error =std deviation/(n)1/2 =0.02

for 99% CI, t=2.58

hence confidence inerval =sample mean -/= t*std error =1.668 ; 1.772

please revert for part D

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