Elementary statisics Math 10so Problem A researcher wishes to determine whether

Question

Elementary statisics Math 10so Problem A researcher wishes to determine whether people with high blood pressure can reduce their blood pressure measured in mm He by following a partitular diet use a significance level of001 to test the hat the treatment group is from a population with a smaller mean than the control group. Use the traditional method of hypothesis testing. Then answer the folowing 35 n2 2B 189 1 2037 S1 38.7 sz 39.2 wy circle which type of Two sample nference this problem represents: 1)Two means independent populations, ei and az known and not assumed equal, Two means independent populations, o and 02 known, 3) Two means, independent populations, on and or unknown but assumed equal, 4.) Two means from two dependent populationk 5.ITwo proportions, 6 l Two variances or standard deviations. write down the nut and the alternative h and Hi: Identify which o identify: Lett- Right. Two taled test the critical values (show the calculation if relevant. What dentify the values for al factors compri ing the Test Statisti he value of the Test stabstit? ca What is vour ranchsion?

Explanation / Answer

a)

2) Two means independent populations, sigma 1 and sigma 2 are unknown.

b)

Null Hypothesis: Blood pressure is treatment group is equal to blood pressure in control group.

Alternative Hypothesis: There is a significant difference in blood pressure in treatment group compare to control group.

c) Two tailed test.

d) critical value = 2.660

e) and f)

test statistics t = -1.48

g) Conclusion : Since t value -1.48 is less than the critical value 2.660, hence we accept null hypothesis and conclude that blood pressure is treatment group is equal to blood pressure in control group.

n1= 35 n2 = 28 Ybar   = 189.1 Xbar   = 203.7 s1   = 38.7 S2   =                39.2 s12   = 1497.69                      S22    =                1536.64 S2p= ((n1-1)*s21 +(n2-1)*s22)/(n1+n2-2)= 1514.93 DF = (s12/n1 + s22/n2)2/{ [ (s12 / n1)2 / (n1 - 1) ] + [ (s22 / n2)2 / (n2 - 1) ] }= 60.42 Assumed difference d = 0 t = [ (Ybar - Xbar) - d ] / Sp*sqrt(1/n1+1/n2) t = -1.47945

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