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Use StatCrunch to estimate a simple linear regression model with life expectancy

ID: 3224300 • Letter: U

Question

Use StatCrunch to estimate a simple linear regression model with life expectancy as the response variable and mean years of schooling as the explanatory variable. All of the questions below refer to this model. Use four decimal place precision in your answers.

Simple linear regression results: Dependent Variable: LifeExp Independent Variable: YrsSchool LifeExp 54.113396 2.2055438 YrsSchool Sample size: 41 R (correlation coefficient) 0.66511717 R-sq 0.44238084 Estimate of error standard deviation: 6.7767475 Parameter estimates: Parameter Estimate Std. Err. DF 95% L. Limit 95% U. Limit Intercept 54.113396 3.6638504 39 46.702559 61.524233 Slope 2.2055438 0.39650994 39 1.4035268 3.0075609 Analysis of variance table for regression model: ss MS F-stat p-value Source DF Model 1 1420.9076 1420.9076 30.940208

Explanation / Answer

Answer to question# 4)

The vlaue of R squared tells us about the percent of varaition

from the very first table of the output we get R sq = 0.4424

Thus percent of variation that can be explained= 0.4424 *100 = 44.24%

Thus the answer to queston# 4 is 44.24%

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bu

For the line of best fit the sum of squares of residuals is Minimized

So if in case we draw another line , the sum of squares would no longer be minimised for it

Thus it would be greateer than 3211.9556

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Hence the correct answer choice are: 3rd and 4th statements