The table to the right shows the results of a survey in which 400 adults from th

Question

The table to the right shows the results of a survey in which 400 adults from the East, 400 adults from the south, 400 adults from the Midwest, and 400 adults from the West were asked if traffic congestion is a serious problem. Complete parts (a) and (b). (a) Construct 89% confidence interval for the proportion of adults from say traffic congestion is a serious problem. The 99% confidence interval for the proportion of adults from say traffic congestion is a serious problem is (Round to three decimal places as needed.) (b) Construct a 99% confidence interval for the proportion of adults from the south who say traffic congestion is a serious problem. Is it possible that these two proportions are equal? Explain your reasoning. The 99% confidence interval for the proportion of adults from the South who say traffic congestion is a serious problem is (Round to three decimal places as needed.) Is it possible that these two proportions are equal? Yes, because the 99% confidence interval for the West overlaps with the 99% confidence interval for the South. No, because the 99% confidence interval for the West does not overlap with the 99% confidence interval for the South.

Explanation / Answer

it cant be possible that these proortions are equal becasue range of CI for both proporions are different.

99% ci = p +- z(a/2)*sqrt(p*(1-p)/n) z(a/2)=z(0.01/2)= 2.575829304 a) lower =0.55-2.576*SQRT(0.55*(1-0.55)/400) 0.486 upper =0.55+2.576*SQRT(0.55*(1-0.55)/400) 0.614 b) lower =0.33-2.576*SQRT(0.33*(1-0.33)/400) 0.269 upper =0.33+2.576*SQRT(0.33*(1-0.33)/400) 0.391

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