State the relevant hypotheses. (Use 01 for low dose treatment and 02 for control

Question

State the relevant hypotheses. (Use 01 for low dose treatment and 02 for control condition Ho: 012 022 Ha: 12 02 Ho: 012 E 022 Ha: 012 02 Ho: 012 E 022 Ha: 012 2022 Ho: 012 E 022 Ha: 012 4022 Calculate the test statistic. Round your answer to two decimal places What can be said about the P-value for the test? O P-value 0.100 O 0.050 P-value 0.100 O 0.010 P-value 0.050 O 0.00 P-value 0.010 P-value 0.00 State the conclusion in the problem context. Reject Ho. The data does not suggest that there is more variability in the low dose weight gains than in control weight gains. O Fail to reject Ho. The data does not suggest that there is more variability in the low dose weight gains than in control weight gains. O Reject Ho. The data suggests that there is more variability in the low dose weight gains than in control weight gains. O Fail to reject Ho. The data suggests that there is more variability in the low dose weight gains than in control weight gains.

Explanation / Answer

Given that,
sample 1
s1^2=3025, n1 =22
sample 2
s2^2 =900, n2 =24
null, Ho: ^2= ^2
alternate, H1: ^2 < ^2
level of significance, = 0.05
from standard normal table,left tailed f /2 =2.036
since our test is left-tailed
reject Ho, if F o < -2.036
we use test statistic fo = s1^1/ s2^2 =3025/900 = 3.36
| fo | =3.36
critical value
the value of |f | at los 0.05 with d.f f(n1-1,n2-1)=f(21,23) is 2.036
we got |fo| =3.361 & | f | =2.036
make decision
hence value of | fo | > | f | and here we reject Ho

ANSWERS
---------------
null, Ho: ^2 = ^2
alternate, H1: ^2 < ^2
test statistic: 3.36
critical value: -2.036
decision: reject Ho

Reject H0. The data suggests that there is more variability In the low-dose weight gains than in control weight gains.

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