Questions 56,57,58,59,60 Find the standardized test statistic t for a sample wit
ID: 3229814 • Letter: Q
Question
Questions 56,57,58,59,60
Find the standardized test statistic t for a sample with n=12, x^bar=13.2, s=2.2, and =0.01 if H_0: mu=12.(1.890 2.132 2.001 1.991 Find the standardized test statistic t for a sample with n=10, x^bar=15.3, s=1.3, and =0.05 if H_0: mu L 16.2. -2.189 -3.010 3.186 2.617 58 use a t-test to test the claim mu=17 at =0.01, given the sample statistics n=12, x^bar=18.2, 58 and s=2.2. Round the test statistic to the nearest thousandth. A shipping firm suspects that the mean life of a certain brand of tire used by its trucks is less than 34,000 miles. To check the claim, the firm randomly selects and tests 18 of these tires and gets a mean lifetime of 33, 200 miles with a standard deviation of 1200 miles. At =0.05, test the shipping firm's claim. Round the test statistic to the nearest thousandth. A local retailer claims that the mean waiting time is less than 6 minutes. A random sample 60 of 20 waiting times has a mean of 4.2 minutes with a standard deviation of 2.1 minutes. At =0.01, test the retailer's claim. Assume the distribution is normally distributed. Round the test statistic to the nearest thousandth.Explanation / Answer
Q56.
Given that,
population mean(u)=12
sample mean, x =13.2
standard deviation, s =2.2
number (n)=12
null, Ho: =12
alternate, H1: !=12
level of significance, = 0.01
from standard normal table, two tailed t /2 =3.106
since our test is two-tailed
reject Ho, if to < -3.106 OR if to > 3.106
we use test statistic (t) = x-u/(s.d/sqrt(n))
to =13.2-12/(2.2/sqrt(12))
to =1.89
Q57.
Given that,
population mean(u)=16.2
sample mean, x =15.3
standard deviation, s =1.3
number (n)=10
null, Ho: =16.2
alternate, H1: !=16.2
level of significance, = 0.05
from standard normal table, two tailed t /2 =2.262
since our test is two-tailed
reject Ho, if to < -2.262 OR if to > 2.262
we use test statistic (t) = x-u/(s.d/sqrt(n))
to =15.3-16.2/(1.3/sqrt(10))
to =-2.189
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