Customer account \"numbers\" for a certain company consist of 2 letters (out of
ID: 3230845 • Letter: C
Question
Customer account "numbers" for a certain company consist of 2 letters (out of 26) followed by 3 (from the set {0, 1, 9}). How many different account are if digits are not allowed? 676,000 B) 468,000 C) 1.404,000 D) 1, 757,000 A box contains 6 green marbles and 4 white marbles. Two marbles are chosen the probability that the first is green and the second is white? 0.333 B) 0.444 C) 0.240 D) 0.267 E) 0.250 The life of light bulbs is distributed normally. The standard deviation of the lifetime is 20 hours and the mean lifetime of a bulb is 600 hours. Find the probability of a bulb lasting for at most 550 hours. Suppose SAT Writing scores are normally distributed with a mean of 500 and a standard deviation of 100 university plans to award scholarship to students whose scores are in the top 8%. What is the minimum score required for the scholarship? 634.1 B) 592 C) 501.4 D) 640.5 Consider the following sample data: 12, 9, 2, 9, 3, 7, 5. Compute the mean and use median of the given data. mean = 6.71, median = 8 B) mean = 6.71, median = 7 C) mean = 6.71, median = 9 D) mean = 3.5, median = 7 E) mean = 7.13, median = 9 A contractor is considering a sale that promises a profit of $35,000 with a probability of 0.7 or a loss (due to bad weather, strikes, and such) of $6000 with a probability of 0.3. What is the expected profit? $29,000 B) $24, 500 C) $22, 700 D) $28, 700 E) $26, 300 5 cards are drawn from a standard deck of 52 playing cards. How many different 5-card hands are possible if the drawing is done without replacement? 1, 245, 450 B) 10.4Explanation / Answer
Hi, Chegg allows to answer 1 question at a time. I will do 2 for you, but kindly repost the others individually for answers. Thank You.
7) Note nCr = n!/[(n-r)! x r!]
We can choose 2 alphabets from 26 alphabets in 26C2 ways = 26!/[(26-2)!x2!] = 325 ways. Each of these 2 alphabets chosen can be arranged in 2! ways = 2 ways eg AB and BA. Therefore total ways of arranging alphabets = 325 x 2 = 650
For the numbers we have to choose 3 out of the 10 numbers in 10C3 ways = 10!/[(10-3)!x3!] = 120 ways. Now these 3 nos chosen can be arranged in 3! = 6 ways eg 123,132,213,231,312,321. Therefore total ways of arranging numbers = 120x6 = 720 ways.
Now, since alphabets and numbers are required to form customer account numbers, they are dependant, and hence total possible account numbers = 650 x 720 = 468,000. OPTION B is the correct answer.
8) Probability of choosing a green ball out of 10 balls = 6/10
Now probability of choosing a white ball out of the remaining 9 balls = 4/9
Therefore the required probability = (6/10) x (4/9) = 24/90 = 0.267
OPTION D is the correct answer.
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