Question 5, all parts. Thank you. 5. A person is to be tested for ESP or clairvo

Question

Question 5, all parts. Thank you.

5. A person is to be tested for ESP or clairvoyance, the ability to see objects that are not visible to the normal senses. The subject is asked to guess which one of ten targets has been randomly selected by a computer. Suppose that in 1,000 trials, he guesses correctly 173 times.

(a) Set up the null hypothesis as a box model.

(b) The SD of the box is . Fill in the blank, using one of the options below, and explain briefly. 0.1 x 0.9 0.173 x 0.827

(c) Make the z-test.

(d) What do you conclude?

Explanation / Answer

(a) Null HYpothesis: H0 : There is no difference in target sensed normally or in effect of ESP or clairvoyance.

Alternative Hypothesis : Ha : There is significant difference in target sensed normally or in effect of ESP or clairvoyance.

(b) Standard Deviation of the box is = sqrt [ 0.1 * 0.9 / 1000] = 0.00949

(c) Z - test

Here pobserved = 173/ 1000 = 0.173

Z = (0.173 - 0.1)/ 0.00949 = 7.6923

Here for alpha = 0.05 Zcritical = 1.96

(d) We can reject the null hypothesis and can conclude that there are significant effect of ESP or clairvoyance to correctly see the objects which are not visible by naked eyes.

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