Readability of Patient Education Materials Many patient education materials (PEM
ID: 3232366 • Letter: R
Question
Readability of Patient Education Materials Many patient education materials (PEMs) published by health organizations are written at abo verage readability levels, which may make it difficult for people to comprehend the information Readability measures the grade level of education necessary to understand written material tothe ssessment of Adult Literacy, 14% of U.S. adults have below basic health literacy. Many studies are performed to determine the readability levels of different PEMs. The table below shows the results of three different studies. Study 1 evaluated PEMs published by the American Clearinghouse for Alcohol and Drug-Information. Study 3 evaluated PEMs from the American Academy of Family Physicians Study Study 2 Study 3 52 11,9 1.84 9.43 Readability level x2 (by grade level 2.2 0.94 1.31 EXERCISES In Exercises 1-3, perform a two-sample z lest 5. Construct a 95% confidence interval for Au1 Aur, where is the mean readability to determine whether the mean readability level in Study 1 and is the mean levels of the two indicated studies are different. readability level in Study 2. Interpret For each exercise, write your conclusion as a the results. (See Extending Concepts in sentence. Use a 0.05 Section 8.1 Exercises. 1. Test the readability levels of PEMs in 6. In a fourth study conducted by the Johns Study 1 against those in Study 2 Hopkins Oncology Center, the mean 2. Test the readability levels of PEMs in readability level of 137 PEMs was 11.1, Study 1 against those in Study 3 with a standard deviation of 1.67 3. Test the readability levels of PEMs in (a) Test the mean readability level of this Study 2 against those in Study 3 study against the level of Study 1. Use 0.01 4. In which comparisons in Exercises l did you find a difference in readability level (b) Test the mean readability level of this Write a summary of your findings study against the level of Study 2. Use 0.01 min khosravani (simn khosravenlogmail.com) on 4/al2013 from 141.142Explanation / Answer
(1)
Data:
n1 = 51
n2 = 52
x1-bar = 11.9
x2-bar = 11.84
s1 = 2.2
s2 = 0.94
Hypotheses:
Ho: 1 = 2
Ha: 1 2
Decision Rule:
= 0.05
Lower Critical z- score = -1.959963985
Upper Critical z- score = 1.959963985
Reject Ho if |z| > 1.959963985
Test Statistic:
SE = {(s1^2 /n1) + (s2^2 /n2)} = (((2.2)^2/51) + ((0.94)^2/52) = 0.334506007
z = (x1-bar -x2-bar)/SE = (11.9 - 11.84)/0.334506006637581 = 0.179368976
p- value = 0.85764799
Decision (in terms of the hypotheses):
Since 0.179368976 < 1.959963985 we fail to reject Ho
Conclusion (in terms of the problem):
There is no sufficient evidence that the population means are significantly different.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.