Consider sampling heights from the population of all female college soccer playe

Question

Consider sampling heights from the population of all female college soccer players in the United States. Assume the mean height of female college soccer players in the United States is = 66 inches and the standard deviation is =3.5 inches. Suppose we randomly sample 100 values from this population and compute the mean, then repeat this sampling process 5,000 times and record all the means we get. Which of the following is the best approximation for the mean of our 5,000 sample means? 6.6 66 100 Suppose we have a large population with mean = 80 and standard deviation = 7.2. Let’s say we randomly sample 100 values from this population and compute the mean, then repeat this sampling process 10,000 times and record all the means we get. Which of the following is the best approximation for the standard deviation of our 10,000 sample means?
A) 7.2
B) .72
C) .072



Consider sampling heights from the population of all female college soccer players in the United States. Assume the mean height of female college soccer players in the United States is = 66 inches and the standard deviation is = 3.5 inches. Suppose we randomly sample 100 values from this population and compute the mean, then repeat this sampling process 5,000 times and record all the means we get. Which of the following is the best approximation for the standard deviation of the 5,000 sample means?
A) .035
B) .35
C) 3.5

Consider sampling heights from the population of all female college soccer players in the United States. Assume the mean height of female college soccer players in the United States is = 66 inches and the standard deviation is =3.5 inches. Suppose we randomly sample 100 values from this population and compute the mean, then repeat this sampling process 5,000 times and record all the means we get. Which of the following is the best approximation for the mean of our 5,000 sample means?

6.6

66

100


please show work if you can. thank you for helo

Explanation / Answer

1)as std error =std deviation/(n)1/2 =0.72

hence option B) .72

2) std error =std deviation/(n)1/2 =0.35

B) .35

3)mean remain same hence  66

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