This problem asks you to do hypothesis testing without calculating precise P-val

Question

This problem asks you to do hypothesis testing without calculating precise P-values but using the table of critical values from your textbook instead. When a poultry farmer uses his regular feed, the newborn chickens have normally distributed weights with a mean of 61.5 oz. In an experiment with an enriched feed mixture, ten chickens are born with the following weights (in ounces). Use the alpha = 0.05 significance level to test the claim that the mean weight is higher with the enriched feed. (a) The sample mean is x = (b) The sample standard deviation is s = (c) The test statistic is t = (d) The critical value is t* = The conclusion is A. There is not sufficient evidence to support the claim that with the enriched feed, the mean weight is greater than 61.5. B. There is sufficient evidence to support the claim that with the enriched feed, the mean weight is greater than 61.5.

Explanation / Answer

Part-a

Sample mean excel formula is =average(65,69.6,63.4,64.8,65.4,62.9,64,63.3,64.3,66.7)

Xbar=64.94

Part-b

Sample standard deviation excel formula is

=stdev(65,69.6,63.4,64.8,65.4,62.9,64,63.3,64.3,66.7)

So, s=1.99

Part-c

Test statistic t=(xbar-61.5)/(s/sqrt(n))=(64.94-61.5)/(1.99/sqrt(10)) =5.47

Part-d

Crititcal value is t*=1.833 using excel function =TINV(0.1,9)

Part-e

As calculated t>t*,we reject the null hypothesis, so part-B is the answer

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