Three people are to be seen in a certain place at 10 o\'clock in the morning. Ea

Question

Three people are to be seen in a certain place at 10 o'clock in the morning. Each person arrives at the pace of the appointment independently in a random time evenly distributed between 10 and 11 in the morning .Each person waits 10 minutes and, if there is no other, he leaves on the other hand, if they can find 2 of them, they wait for the other until 11 in the morning. (a) What is the probability than no pair of people will be found? b) what is the probability that the 3 persons will be found? (c) What is the least time that each person should wait in such a way that the probability that the 3 persons are found is greater than 1/2? Solution a) 8/27 b) 91/216 c) 60 (1-1/cubicroot 2) minutes.

Explanation / Answer

I can see that you already have the answers to all the questions that is

For (a) answer is 8/27

For (b) answer is 91/216

And for (c) answer is 60*(1-1/2).

Let me know if u need any other help regarding these questions

Thank you

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