Computer output for a regression line to predict the number of Facebook friends

Question

Computer output for a regression line to predict the number of Facebook friends a student will have, based on a normalized score of the grey matter density in the areas of the brain associated with social perception and associative memory is given below. Data for the sample of n = 40 students are stored in FacebookFriends.

Pearson correlation of GMdensity and FBfriends =0.436
P-Value = 0.005
-------------------------
The regression equation is FBfriends = 367 + 82.4 GMdensity

R-Sq(adj) = 16.9%

A) The slope of the regression analysis is: 82.4

The standard error for the slope is: 27.58.

C) Use the information from part (A) to find a 95% confidence interval for the slope. Use t-values rounded to three decimal places.

Round your answers to two decimal places.

_____ to _____

Explanation / Answer

(B) t=Coef/(SE Coef)=82.45/27.58=2.99

P-value=0.0048 ( using ms-excel command =TDIST(2.99,38,2))

at alpha=0.05 we Reject null hypothesis as the p-value is less than alpha=0.05

(C)  to find a 95% confidence interval for the slope, t-values=2.024 (using ms-excel command =TINV(0.05,38))

confidence interval=82.45±2.024*27.58=82.45±55.82=(26.63,138.27)

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