In a survey of 2606 adults, 1489 say they have started paying bills online in th
ID: 3242612 • Letter: I
Question
In a survey of 2606 adults, 1489 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is left parenthesis nothing comma nothing right parenthesis , . (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. A, The endpoints of the given confidence interval show that adults pay bills online 99% of the time. B. With 99% confidence, it can be said that the sample proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval. C. With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval.
Explanation / Answer
The statistical software output for this problem is:
One sample proportion confidence interval:
p : Proportion of successes
Method: Standard-Wald
99% confidence interval results:
Hence,
99% confidence interval will be:
(0.546, 0.596)
Interpretation: Option C is correct.
Proportion Count Total Sample Prop. Std. Err. L. Limit U. Limit p 1489 2606 0.57137375 0.0096942077 0.54640313 0.59634438Related Questions
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