In a recent court case it was found that during a period of 11 years 867 people
ID: 3244617 • Letter: I
Question
In a recent court case it was found that during a period of 11 years 867 people were selected for grand jury duty and 39% of them were from the same ethnicity. Among the people eligible for grand jury duty, 78.9% were of this ethnicity. Among the people eligible for grand jury duty, 78.9% were of this ethnicity. Use a 0.01 significance level to test the claim that the selection process is biased against allowing this ethnicity to sit on the grand jury. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.
What is the test statistic?
A) z = _ ( round to 2 decimal places )
B ) P value = _ ( round to 2 decimal places)
Choose between Is or Is not
C) There ( Is ) or ( Is not ) sufficient evidence to support the claim that the polygraph results are correct less than 80%of the time.
Explanation / Answer
Solution:-
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: P > 0.789
Alternative hypothesis: P < 0.789
Note that these hypotheses constitute a one-tailed test.
Formulate an analysis plan. For this analysis, the significance level is 0.01. The test method, shown in the next section, is a one-sample z-test.
Analyze sample data. Using sample data, we calculate the standard deviation () and compute the z-score test statistic (z).
= sqrt[ P * ( 1 - P ) / n ]
= 0.01386
z = (p - P) /
z = - 28.8
where P is the hypothesized value of population proportion in the null hypothesis, p is the sample proportion, and n is the sample size.
Since we have a one-tailed test, the P-value is the probability that the z-score is less than - 28.8.
Thus, the P-value = less than 0.0001
Interpret results. Since the P-value (almost 0) is less than the significance level (0.01), we have to reject the null hypothesis.
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