Find the margin of error and confidence interval (CI) if the necessary requireme

Question

Find the margin of error and confidence interval (CI) if the necessary requirements are satisfied: The braking distances of a simple random sample of cars: 95% confidence level; n = 32, mean x = 137 ft., sigma is known to be 7 ft. E= CI = Find the margin of error and the confidence interval for a sample of chocolate chip cookies that has a n = 40, a mean x bar = 23.95 chips and a standard deviation sigma = 2.55 chips. Construct a 99% confidence interval estimate of the mean number of chocolate chip cookies. E= CI=

Explanation / Answer

4 ) here std error =std deviation/(n)1/2 =1.2374

for 95% CI, z=1.96

hence margin of error E =z*std error =2.4253

CI =sample mean -/+E =134.5747 ; 139.4253

5)

here std error =std deviation/(n)1/2 =0.4032

for 99% CI, z=2.5758

hence margin of error E =z*std error =1.0385

CI =sample mean -/+E =22.9115 ; 24.9885

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