In a maze running study, a rat in a T maze and the result of each run recorded.

Question

In a maze running study, a rat in a T maze and the result of each run recorded. A reward in the form of food is always placed at the right exit. If learning is taking place, the rat will choose the right exit more often than the left. In no learning is taking place, the rat should randomly choose either exit. Suppose that the rat is given n = 100 runs in the maze and that he chooses the right exit x = 64 times. Would you conclude that learning is taking place? 1. H_0: P_[a][b] vs. H_1: P_[c][d] 2.taltbl VS. 2. Test statistics: z = [e] 3. Reject H_0 if z[f][g]. 4. [h] reject the null hypothesis since z_ [i][j]. 5. There [k] sufficient evidence to conclude that the learning is taking place.

Explanation / Answer

1) Ho:p=0.5

H1:p>0.5

2)std error =(p(1-p)/n)1/2 =0.05

phat=64/100=0.64

hence test stat z=(phat-p)/std error =(0.64-0.5)/0.05=2.8

3) Reject Ho if z>1.645 (for 0.05 level

4) we can reject the null hypothesis. since zobs>1.645

5) ther is sufficient evidence to conclude..................

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.