F = P = variety length bihai 46.48 bihai 47.51 bihai 48.52 bihai 48.73 bihai 46.
ID: 3249488 • Letter: F
Question
F =
P =
variety length bihai 46.48 bihai 47.51 bihai 48.52 bihai 48.73 bihai 46.05 bihai 46.01 bihai 48.19 bihai 50.48 bihai 47.92 bihai 48.1 bihai 48.46 bihai 48.23 bihai 48.73 bihai 45.67 bihai 47.66 bihai 49.16 red 40.7 red 39.23 red 35.92 red 42.84 red 41.15 red 39.03 red 39.86 red 40.35 red 39.69 red 39.35 red 41.13 red 37.13 red 38.36 red 39.28 red 39.38 red 39.79 red 36.31 red 40.38 red 40.9 red 40.27 red 38.33 red 39.66 red 40.4 yellow 34.71 yellow 36.07 yellow 34.69 yellow 35.57 yellow 36.47 yellow 35.37 yellow 33.74 yellow 35.88 yellow 35.51 yellow 35.04 yellow 35.01 yellow 35.61 yellow 35.05 yellow 36.69 yellow 36.58
flower type n s H. bihai H. caribaea red H. caribaea yellowExplanation / Answer
F=363.7362
P=0.0000
flower type Count xbar s Sx bihai 16 47.8688 1.2840 0.3210 red 23 39.5409 1.5772 0.3289 yellow 15 35.4660 0.8036 0.2075 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 1262.398 2 631.1988 363.7362 0.0000 3.1788 Within Groups 88.50132 51 1.7353 Total 1350.899 53Related Questions
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