Veterinary researchers at a major university veterinary hospital calculated a 99
ID: 3249581 • Letter: V
Question
Veterinary researchers at a major university veterinary hospital calculated a 99% confidence interval for the average age of horses admitted for laminitis, a foot disease that leaves the horse severely lame, as 6.3 to 7.4 years. Based on this information we conclude that: 99% of all horses admitted for laminitis are between 6.3 and 7.4 years old. All of the above we are 99% confident that the true mean age of horses with laminitis is between 6.3 and 7.4 years old. we can be 100% sure that the average age of horses admitted with laminitis is between 6.3 and 7.4 years. You measure the lifetime of a random sample of 64 tires of a certain brand. The sample mean is =50 months. Suppose that the lifetimes for tires of this brand follow a Normal distribution, with unknown mean mu and standard deviation sigma=5 months. A 99% confidence interval for mu is: 48.78 to 51.22. 48.39 to 51.61. 49.80 to 50.20. 40.2 to 59.8. 36. A statistician wishing to test a hypothesis that students score at least 75% on the final exam in an introductory statistics course decides to randomly select 20 students in the class and have them take the exam early. The average score of the 20 students on the exam was 78% and the standard deviation in the population is known to be sigma= 15%. The P-value for the hypothesis H_o: mu= 75 vs. H_0: mu > 75 is 0.186. 0.371 The answer cannot be determined with information provided. 0.814.Explanation / Answer
35)
n = 64 , mean = 50 , s = 5
z value at 99% CI = 2.576
CI = mean +/- z * ( s / ssqrt(n))
= 50 +/ -2.576 * ( 5 / sqrt(64))
= (48.39 , 51.61)
36)
n = 20 , mean = 75 , x = 78 , s = 15
z = ( x -mean) / ( s / sqrt(n))
= ( 78 - 75) / ( 15 / sqrt(20))
= 0.894
p value is calculated using z = 0.894 for one tailedtest with 0.05 significance level.
P value = 0.186
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