Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

IUUl. J. ASSIUlltflent 3 Final Final Exam This Question: 15 pts 4 19 of 20 (16 c

ID: 3251346 • Letter: I

Question

IUUl. J. ASSIUlltflent 3 Final Final Exam This Question: 15 pts 4 19 of 20 (16 complete This Test: 300 pts possi la Queston Het t Assume that a simple random sample has been selected from anomaly dstituted population and rest the given dam ldenery the nul ypatheses, statisti Prae stale ne and test mint has a specacation that a particular coin has a mean weigt of 25g Asample of coim was colected These coins have a mean weight and a deviasonofae182 use aa significance level to test the claim that this sample is from apopulation with a mean weight equal to 25g Do the coins appear to conform to the speciicasons of the coin mint? What are the hypotheses? O A. Ho RE25g O C. How 2.5g p

Explanation / Answer

Solution:-

State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: = 2.5

Alternative hypothesis: 2.5

Note that these hypotheses constitute a two-tailed test. The null hypothesis will be rejected if the sample mean is too big or if it is too small.

Formulate an analysis plan. For this analysis, the significance level is 0.05. The test method is a one-sample t-test.

Analyze sample data. Using sample data, we compute the standard error (SE), degrees of freedom (DF), and the t statistic test statistic (t).

SE = s / sqrt(n)

S.E = 0.002995

DF = n - 1 = 37 - 1

D.F = 36

t = (x - ) / SE

t = 2.995

where s is the standard deviation of the sample, x is the sample mean, is the hypothesized population mean, and n is the sample size.

Since we have a two-tailed test, the P-value is the probability that the t statistic having 37 degrees of freedom is less than - 2.995 or greater than 2.995.

Thus, the P-value = 0.00494

Interpret results. Since the P-value (0.00494) is less than the significance level (0.05), we have to reject the null hypothesis.

From the above test we do not have sufficient evidence in the favor of the claim that mean is equal to 2.5.

No, Since the coins seems to come from a population with a mean weight different from 2.5.

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote