8.1 INTRODUCTION 225 results in the same probability. To find the 31 percentile,

Question

8.1 INTRODUCTION 225 results in the same probability. To find the 31 percentile, enter the argument .31 the invN option of DISTR. This results in a orm score of in 49580307. The 31 percentile is z 0,49580307a 1400.48 0.49580307(06-328) 1347.757224- A ternatively You can use the function invNorm(.31,1400.48,106, 328) 1347.757224 EXERCISES FOR SECTION 8.1 8.1 Consider a normal population with the following values to u 135 and a 5. Convert 2-scores: a. 142 b. 135 c. 102 d. 140 e. 130 8.2 Consider a normal population with 1.6 and o 2.1. Convert the follow ing values to 2-scores: a. 3.7 b. 1.6 1.3 d. 1.8 8.3 Consider a normal population with u 50 and a 6. Convert the following 2-scores to original units: c, 1.2 2.5 e. 4.5 8.4 Consider a normal population with pu 5.6 and o 1.2. Convert the follow- ing z-scores to original units: d. 1.2 e. 3.0 2.1 c. 0 1.5 8.5 Calculate the area under the standard normal curve between b. 0.25 and 2 1.25 a. 0.00 and 1.25 c. 2 1.25 and 0.25 d. 1.25 and 0 8.6 Consider a normal variable x with Au 35 and a 20 a. Find Pr (x

Explanation / Answer

8.1)
z = (x - mu)/sigma

8.2)

8.3)

x = mu + z*sigma

8.4)

a 142 =(142-135)/5 1.4 b 135 =(135-135)/5 0 c 102 =(102-135)/5 -6.6 d 140 =(140-135)/5 1 e 130 =(130-135)/5 -1

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