Answer Question 10: A classic tale told lo teachers for students missing class i

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Answer Question 10:

A classic tale told lo teachers for students missing class is "my car had a flat tire." On the makeup test, the teacher asked the students to identity the particular tire that went flat. The results of the 40 student responses are below. Use a 0.05 significance level to test the claim that the results fit a uniform distribution. The table below includes results from a polygraph lie-detector experiment. In each case, it was known if the subject lied or didn't lie, so the table indicates whether the polygraph test was correct. Use a 0.05 significance level to test the claim that whether a subject lies is independent of the polygraph test indication. Do the results suggest that polygraphs are effective in distinguishing between truths and lies? A research group polls 764 randomly selected adults, and asked them if they would like someone like Homer Simpson to be their neighbor. 589 said no. a. Construct a 94% confidence interval of the percentage of all adults who do not want Homer Simpson to be their neighbor. b. Is it correct tor a newspaper headline to read: "80% of people do not want to live next to Homer Simpson"? Explain your reasoning. c. How many people need to be surveyed if you want 98% confidence that the margin of error is two percentage points? A secret shopper times how long it takes her to wait in line at the supermarket before beginning her checkout. Her calculated times, in minutes, are below: a. Construct u 95% confidence interval estimate for the population mean of all wait times at this supermarket. b. Construct a 95% confidence interval estimate for the standard deviation for all wait times at this supermarket. c. What is the five number summary for this data set and explain the meaning of each number. A coin is tossed 15 times. A person who claims to have the ability to predict whether the coin will land heads is asked to predict the outcome of each toss. She correctly

Explanation / Answer

10) She correctly predicts 10/15 tosses giving a success rate of 10/15 = 2/3.

      If she randomly guesses, then prob of calling heads when coin flips heads is 2/3 and getting it wrong = 1/3

      Required Prob is P(atleast 10 or more tosses correct)

      She can only be right or wrong, so, distirbution is binomial with p = 2/3

      P(X=k) = C(n,k)pkqn-k where k is no of success

      P(X>= 10) = P(X=10) + P(X=11) + P(X=12) + P(X=13) + P(X=14) + P(X=15)

                       = Sumk;10-15(C(15,k)(2/3)k(1/3)15-k)

                       = .62

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