Personnel tests are designed to test a job applicants cognitive and/or physical

Question

Personnel tests are designed to test a job applicants cognitive and/or physical abilities. A particular dexterity test is administered nationwide by a private testing service It is known that for all tests administered last year, the distribution of scores was approximately normal with mean 72 and standard deviation 8.1. A particular employer requires job candidates to score at least 77 on the dexterity test. Approximately what percentage of the test scores during the past year exceeded 77? The testing service reported to a particular employer that one of its job candidate's scores fell at the 98th percentile of the distribution (i.e., approximately 98% of the scores were lower than the candidate's, and only 2% were higher). What was the candidate's score?

Explanation / Answer

a) z=(x-mean)/sigma=(77-72)/8.1=0.6172

P(z>0.6172) can be found from normal tables as 1-0.731449=0.268551

b) z for probability greater than 0.98 is 2.053749

2.053= (x-72)/8.1

or x = 72+8.1*2.053=88.629

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.