type String 1 0 None None 18 Left Nominal Input Part 2 : Please answer the follo

Question

type String 1 0  None None 18 Left Nominal Input   

Part 2 : Please answer the following:

1. Which z-score represents a greater deviation from the mean, z = 1.64, or z = -2.54? Explain.

2. Suppose you collect some data and find that it follows a normal distribution. You find that the z-score for a particular point is 2. What percentile is this score in? What is the interpretation of a percentile?

3.You administer a test to Group A and Group B. You want to determine if on average, Group A scores higher than Group B. State the null and alternative hypotheses.

4. How do the mean and variance define a normal distribution? In other words, how do these parameters affect the shape, and what is the interpretation of the shape?

5 (Extra Credit). Look at the histogram on slide 16. Each bar represents the probability of observing that particular combination of dice. If you were to sum all the bars together, what would the total be? That is, if you took P(D=3) + P(D=4) + ... P(D=18), what would the total be? This answer should require no calculation.

**** DATA:

score type 11.42578720134370 A 10.85742539165350 A 9.31337371949495 A 10.44951932474110 A 10.61338150655250 A 9.85173888869614 A 10.79828915085010 A 9.34610344287797 A 12.13299565502180 A 8.47362004819231 A 9.78029536372566 A 9.99118913382795 A 9.66644191120154 A 10.53421350073270 A 9.42083527137901 A 11.24492890148330 A 10.46875771027510 A 11.55551287818810 A 9.23293388719641 A 9.14994856749139 A 9.62416514445747 A 10.98530997989950 A 10.42689197261100 A 11.49169677814810 A 8.60663686365064 A 8.08366009682623 B 7.60300697588410 B 8.27636301486757 B 7.93065447866175 B 8.95843730400666 B 7.44042918402056 B 9.05720658910886 B 7.45639804092888 B 6.36544700840028 B 8.63782320150698 B 7.99752563000492 B 7.20080538000171 B 7.57677912344459 B 9.26341586856752 B 7.67465562602318 B 6.71481004995297 B 8.51515186267148 B 9.30659378113112 B 7.08030562836956 B 8.91860940624242 B 9.17633036766511 B 8.64368427802216 B 8.54402523882834 B 8.43429362625656 B 8.42776429193225 B

Explanation / Answer

1. the probability value correspinding to z=-2.54 is 0.005 and z=1.64 is 0.94 ,apparnetly p-vlaue for z=-2.54 is far more from mean value.

2. corresponding p-value for z=2 is

3. Ho: null hypothesis : the mean score for group A nad B are same.

Ha: Ua>Ub

one-tailed test to be used

4. = 0 and = 1 defines a standard normal distribution

0.98 ,so percentile is 98

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