As part of the study on ongoing fright symptoms due to exposure to horror movies

Question

As part of the study on ongoing fright symptoms due to exposure to horror movies at a young age, the following table was presented to describe the lasting impact these movies have had during bedtime and waking life:

(a) What percent of the students have lasting waking-life symptoms? (Round your answer to two decimal places.)
___%

(b) What percent of the students have both waking-life and bedtime symptoms? (Round your answer to two decimal places.)
___%

(c) Test whether there is an association between waking-life and bedtime symptoms. State the null and alternative hypotheses. (Use = 0.01.)

Null Hypothesis: (choose the best answer)

H0: Waking symptoms cause bedtime symptoms.

H0: There is no relationship between waking and bedtime symptoms.   

H0: Bedtime symptoms cause waking symptoms.

H0: There is a relationship between waking and bedtime symptoms.

Alternative Hypothesis: (choose the best answer)

Ha: Bedtime symptoms cause waking symptoms.

Ha: Waking symptoms cause bedtime symptoms.    

Ha: There is no relationship between waking and bedtime symptoms.

Ha: There is a relationship between waking and bedtime symptoms.

State the 2 statistic and the P-value. (Round your answers for 2 and the P-value to three decimal places.)

Conclusion: (choose the best answer)

*We have enough evidence to conclude that there is a relationship.

*We do not have enough evidence to conclude that there is a relationship.    

     Waking
symptoms Bedtime symptoms Yes      No Yes 36 32 No 32 19

Explanation / Answer

a)  percent of the students have lasting waking-life symptoms=(68/119)*100=57.14%

b) percent of the students have both waking-life and bedtime symptoms =(36/119)*100=30.25%

c) null hypothesis: H0: There is no relationship between waking and bedtime symptoms

Alternative Hypothesis: Ha: There is a relationship between waking and bedtime symptoms.

applying chi square test of independence on above:

2 =1.144

df =1

p value =0.285

Conclusion:

*We do not have enough evidence to conclude that there is a relationship.

Observed O yes No Total Yes 36 32 68 No 32 19 51 Total 68 51 119 Expected E=rowtotal*column total/grand total yes No Total Yes 38.857 29.143 68 No 29.143 21.857 51 Total 68 51 119 chi square =(O-E)^2/E yes No Total Yes 0.210 0.2801 0.490 No 0.280 0.373 0.654 Total 0.490 0.654 1.144

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