One study reports that 28% of newly hired MBAs are confronted with unethical bus
ID: 3265157 • Letter: O
Question
One study reports that 28% of newly hired MBAs are confronted with unethical business practices during their first year of employment. One business school dean wondered if her MBA graduates had similar experiences. She surveyed recent graduates from her school's MBA program to find that 23% of the 129 graduates from the previous year claim to have encountered unethical business practices in the workplace. Can she conclude that her graduates experiences are different? What are the null and alternative hypotheses? A. H_0: p = 0.23 vs. H_A: p > 0.23 C. H_0: p = 0.23 vs. H_A: p notequalto 0.23 E. H_0: p = 0.28 vs. H_A: p notequalto 0.28 B. H_0: p notequalto 0.28 vs. H_A: p = 0.28 D. H_0: p = 0.28 vs. H_A: P 0.28 What is the value of the test statistic? A. The test statistic is B. The assumptions and conditions are not met, so the test cannot proceed. What is the P-value of the test statistic? A. The assumptions and conditions are not met, so the test cannot proceed. B. P-value = Can she conclude that her graduates' experiences are different? Assume alpha = 0.05. A. Fail to reject the null hypothesis. There is sufficient evidence that the rate of unethical business practice exposure is different from that reported in the study. B. Reject the null hypothesis. There is insufficient evidence that the rate of unethical business practice exposure is different from that reported in the study. C. Reject the null hypothesis. There is sufficient evidence that the rate of unethical business practice exposure is different from that reported in the study. D. Fail to reject the null hypothesis. There is insufficient evidence that the rate of unethical business practice exposure is different from that reported in the study. E. No conclusion can be drawn because the conditions and assumptions were not met for the hypothesis test.Explanation / Answer
for hypothesis: option E is correct
here p=0.28 and n=129
std error =(p(1-p).n)1/2 =0.0395
phat=0.23
therefore test stat =(phat-p)/std error =-1.2648
p value =0.2059
option D is correct. fail to reject the null..................
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