I need help with Number 6 Cunclude that the Outcome Frequency Outcome Frequency
ID: 3268731 • Letter: I
Question
I need help with Number 6
Explanation / Answer
Q.6
Null HYpothesis : H0 : The number of rounds played per week is independent of the day os weeks they are played.
Alternative Hypothesis : Ha : The number of rounds played per week is dependent of the day os weeks they are played.
Significance leval alpha = 0.05
Here we will use the goodness of fit Chi - square test (indendence) Test .
The Observed table is given in the question. Now we will calculate the expected value which is
Expected value of rounds shall be played on each day = (124 + 74 + 104 + 98 + 120)/5 = 104
Value of CHi - square X2= 15.31
Here Degree of freedom = 5 -1 = 4 and alpha = 0.05
so critical value of chi-square X2cr = 9.488
Here, X2 > X2cr so we can reject the null hypothesis and can conclude that the number of rounds played per week is dependent on the day of week they are played.
Day Observed (O) Expected (E) (O -E) (O-E)^2 (O-E)^2/E Monday 124 104 20 400 3.85 Tuesday 74 104 -30 900 8.65 Wednesday 104 104 0 0 0 Thursday 98 104 -6 36 0.35 Friday 120 104 16 256 2.46 520 15.31Related Questions
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