1) (size) = 496.484*(cost) + 0.265 2) (cost) = 496.484*(size) + 0.265 3) (cost)
ID: 3269626 • Letter: 1
Question
1) (size) = 496.484*(cost) + 0.265 2) (cost) = 496.484*(size) + 0.265 3) (cost) = 0.265*(size) + 496.484 4) (size) = 0.265*(cost) + 496.484 5) (cost) = 0.265*(size) 1) (size) = 496.484*(cost) + 0.265 2) (cost) = 496.484*(size) + 0.265 3) (cost) = 0.265*(size) + 496.484 4) (size) = 0.265*(cost) + 496.484 5) (cost) = 0.265*(size) 1) (size) = 496.484*(cost) + 0.265 2) (cost) = 496.484*(size) + 0.265 3) (cost) = 0.265*(size) + 496.484 4) (size) = 0.265*(cost) + 496.484 5) (cost) = 0.265*(size) Coef 496.484 134.053 3.7 0.265 Stdev t-ratio P 0.006 0.043 Constant size 0.1104 2.4 s = 5.684 R-sq 41.92% R-sq (adj ) = 34 . 668 = Analysis of Variance SOURCE Regression Error Total DF 1 186.5 258.5 445 MS 186.5 32.3 5.77 0.043Explanation / Answer
from above given output:
cost =intercept +slope*size =0.265*size +496.484
therefore option 3 is correct
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