Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

When testing for the independence in a contingency table with 3 rows and 4 colum

ID: 3269861 • Letter: W

Question

When testing for the independence in a contingency table with 3 rows and 4 columns, how many degrees of freedom will the test statistic have? 1.5 2.7 3.6 4.12 What is the appropriate test to use if you want to determine whether hero is evidence that the proportion of successes is higher in group 1 than in group 2 and we have obtained independent samples from the two groups? Both of the Z test and the chi-square test. The Z test The chi-square test Neither the Z test nor the chi-square test Which of the following values cannot occur in the chi-square distribution? 0.61 100.0 38.4 -2.45

Explanation / Answer

Question 1 : Degree of freedom = (n-1) * (k-1) = (2-1) * (3-1) = 6 Option C is correct.

Question 2: Here we will use only Z test because for proportion hypothesis testing we use Z test. CHi-square can't be used here as we are not checking goodness of fit or independence test.

Question 3 OPtion D is correct. The value (-2.45) because value of chi-square can't be negative

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote