In a sample of 1000 u.s. adults, 186 In a sample of 1000 U.S adults, 186 dine ou

Question

In a sample of 1000 u.s. adults, 186

In a sample of 1000 U.S adults, 186 dine out at a resaurant more than once per week Two US adults are selected at random from the popuáation of al u S adults without replacement Assuming the sample is (a) Find the probability that both adults dine out more than once per week The probability that both adults dine out more than once per week is (Round to three decimal places as needed) (b) Find the probsbility that neither adult dines out more than once per week The probability that neither adult dines out more than once per week is Round to three decimal places as needed.) (c) Find the probability that at least one of the two adults dines out more than once per week opresentative of at U S adults,complete parts (a) thiough (d) The probability that at least one of the two adults dines out more than once per week Round to three decimal places as needed) (0) Which of the events can be considered unusual? Explain Select al that apply event in part (a) is unusual because its probability is less than or equal to 0.05 B. The event in part (C) es unusual because its probabitys less than or equal to 0 05 C. None of these events are unusual D.T The event in pat ibi is unusual because its probability is less than or equal to 0 05

Explanation / Answer

Solution:-
a) (186/1000)x(185/999) = 0.034

b) (814/1000)x(813/999) = 0.662

c) 1 - 0.662 = 0.338

d) option A. the event in part(a) is unusual because its probability is less than or equal to 0.05

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.