A mole of nickel has a maze of 59g. and one mobile electron is released by each

Question

A mole of nickel has a maze of 59g. and one mobile electron is released by each atom in metallic nickel. The density of nickel is about 8.8 g/cm^3. a) How many atoms of nickel are present in a mass of 59 g of nickel? (b) How many atoms of nickel are present in 8.8 g of the metal? (c) What is the mobile electron density for nickel? An proton is moving upward with speed 3 times 10^6 m/s. What is the magnitude and direction of the proton's magnetic field at each location shown. Points A - F are 8 cm from the charge?

Explanation / Answer

solving first question of the page

Given atomic mass of nicket=59 g

so mass of 1 mole=59 g

Number of atom in 1 mole =Avogadro number=6.023*10^23

so number of atom in 59 g Nickel=6.023*10^23

(b) number of moles in 8.8 g=8.8/59

number of atom=8.98*10^22

(c)1 atom contain 1 electron

number of atom in 8.8 g=8.98*10^22=number of electron

volume of 8.8g=1 cm^3=1*10^(-6) m^3

electron density=number of electron/volume in m^3=8.98*10^28

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