A block is pushed up an incline by an applied force that is directed parallel to

Question

A block is pushed up an incline by an applied force that is directed parallel to the The coefficient of kinetic friction between the block and the incline is (0.2). The mass of block is 5 Kg, and the incline angle is 30 degrees. Also, the block moves up the incline at a constant speed of 3.5 m/s. After the block has moved 1.5 meters up the incline, a) Find the work done by gravity b) Find the work done by the applied force c) Find the work done by friction d) Find the change in kinetic energy of the block

Explanation / Answer

Work done by gravity=-mgsin30×1.5=-5×9.8×0.5×1.5=-36.75J

Work done by applied force F=(mgsin30+umgcos30)×1.5=49.48J

Work done by frictional force=umgcos30×1.5=-12.73J

As the block is moving with constant speed so change in K.E.is zero

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