Nandemonaiya Mitsu × Mail ri@ Advanced Physics quest × > d wwww.webassign.net/we

Question

Nandemonaiya Mitsu × Mail ri@ Advanced Physics quest × > d wwww.webassign.net/web/Student/Assignment. Responses/last?dep-17002059 4. -120 polnts NorEngStatics1 4.P.012. My Notes Ask Your Teach A 150 lb force acts at A as shown on the baby blue plate. 8.5 ft 4.4 ft 5.3 ft 8.5 ft 150 lb (a) Determine the moment of the force about points B, C, and D In ft lb. ME magnitude direction ft Ib Mc. magnitude direction ft Ib MD magnitude direction ft lb (b) Determine the shortest distance from each polnt to the line of action of the force In feet. ft ft ft 9:27 PM lype here to search 9/18/2017

Explanation / Answer

a] MB = F r sin theta

= 150* cos 35 degree * (8.5+4.4)

= 1585 lb-ft

MC =  150* cos 35 degree * (8.5+4.4) -  150* sin 35 degree * (8.5-5.3)

= 1310 lb-ft

MD = 150* cos 35 degree * 8.5 -  150* sin 35 degree *8.5

= 313 lb-ft

b] dB = MB/150 = 1585/150 = 10.57 ft

dC = MC/150=1310/150= 8.73 ft

dD = MD/150 = 313/150 = 2.087 ft

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.