please explain thanks . Consider a typical life span of 100 years for a human of

Question

please explain
thanks

. Consider a typical life span of 100 years for a human of height 1.7 m. 1. Compute the difference in age of your head versus your toe, assuming you sleep 8 hours per day. 2. How does the same work out for a giraf with height 5 m. 2. Jane is cycling home with a velocity of 10 m/s. She calls home, telling she will arrive in 15 minutes. 1, what is Jane's Lorentz factor? 2. How long does her family wait at home for her arrival? 3. Jack is fying home at an altitude of 6 km and a velocity of 720 m/s. He calls home, telling he will arrive at the Inchon airport (ICN) in 1 hr 1 . What is Jack's Lorentz factor? 2. His wife happens to at ICN already. How long does she wait for his arrival? The U-235 nucleus has a diameter D 15 fm. Fission of a U-235 nucleus produces fast neutrons with a kinetic energy broadly distributed about 1 MeV. The total mass energy of a neutron is close to 1 GeV 1. What is the Lorentz factor of such fast neutrons? 2. Consider a semi-classical approximation to the production of fast neutrons in the fission of U-235 nuclei and assume a constant acceleration over the radius R D/2. What is ? Compute the distance to the associated Rindler horizon.

Explanation / Answer

1, for span of 100 years

the toes are at slow ticking clock

then to = 100 years

for head then the clock is ticking faster with time tf

to = tf*sqroot(1 - rs/r) ( fROM SCHWARZCHILD METRIC)

where rs = schwarzchild radius for earth = 8.87*10^-3

r = 6371,000 + 1.7 = 6371,001.7 m ( distance of head form the centre of the earth)

so, tf = 100/sqroot(1 - rs/r) = 100.00000006961 years

so difference in age of head and toe = 0.00000006961 years = 2.196 seconds over a span of 100 years

2. for a giraf, t = 6371,005 m

so, tf = 100/sqroot(1 - rs/r) =100.00000006961225120104214345596 years

so difference in age of head and toe = 6.961225*10^-6 years = 2.19679 seconds over a span of 100 years

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